48333424049503 has 4 divisors (see below), whose sum is σ = 48334237707040. Its totient is φ = 48332610391968.

The previous prime is 48333424049413. The next prime is 48333424049507. The reversal of 48333424049503 is 30594042433384.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-48333424049503 is a prime.

It is a super-2 number, since 2×48333424049503² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (48333424049507) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 406739658 + ... + 406858471.

It is an arithmetic number, because the mean of its divisors is an integer number (12083559426760).

Almost surely, 2^{48333424049503} is an apocalyptic number.

48333424049503 is a deficient number, since it is larger than the sum of its proper divisors (813657537).

48333424049503 is an equidigital number, since it uses as much as digits as its factorization.

48333424049503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 813657536.

The product of its (nonzero) digits is 14929920, while the sum is 52.

The spelling of 48333424049503 in words is "forty-eight trillion, three hundred thirty-three billion, four hundred twenty-four million, forty-nine thousand, five hundred three".