4838400000037 has 2 divisors, whose sum is σ = 4838400000038. Its totient is φ = 4838400000036.

The previous prime is 4838399999969. The next prime is 4838400000073. The reversal of 4838400000037 is 7300000048384.

4838400000037 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (4838400000073) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3295118040516 + 1543281959521 = 1815246^2 + 1242289^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4838400000037 is a prime.

It is a super-2 number, since 2×4838400000037² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4838399999951 and 4838400000005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4838400000437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2419200000018 + 2419200000019.

It is an arithmetic number, because the mean of its divisors is an integer number (2419200000019).

Almost surely, 2^{4838400000037} is an apocalyptic number.

It is an amenable number.

4838400000037 is a deficient number, since it is larger than the sum of its proper divisors (1).

4838400000037 is an equidigital number, since it uses as much as digits as its factorization.

4838400000037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64512, while the sum is 37.

The spelling of 4838400000037 in words is "four trillion, eight hundred thirty-eight billion, four hundred million, thirty-seven", and thus it is an aban number.