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4841108794937 is a prime number
BaseRepresentation
bin100011001110010100010…
…0100011110111000111001
3122010210202012021121010102
41012130220210132320321
51113304042322414222
614143550310325145
71006521121542212
oct106345044367071
918123665247112
104841108794937
1115a7114786458
126622a56597b5
1329168c76752c
1412a44d220409
1585ddd2a5d92
hex4672891ee39

4841108794937 has 2 divisors, whose sum is σ = 4841108794938. Its totient is φ = 4841108794936.

The previous prime is 4841108794933. The next prime is 4841108794961. The reversal of 4841108794937 is 7394978011484.

4841108794937 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2816006185216 + 2025102609721 = 1678096^2 + 1423061^2 .

It is a cyclic number.

It is not a de Polignac number, because 4841108794937 - 22 = 4841108794933 is a prime.

It is not a weakly prime, because it can be changed into another prime (4841108794933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2420554397468 + 2420554397469.

It is an arithmetic number, because the mean of its divisors is an integer number (2420554397469).

Almost surely, 24841108794937 is an apocalyptic number.

It is an amenable number.

4841108794937 is a deficient number, since it is larger than the sum of its proper divisors (1).

4841108794937 is an equidigital number, since it uses as much as digits as its factorization.

4841108794937 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48771072, while the sum is 65.

The spelling of 4841108794937 in words is "four trillion, eight hundred forty-one billion, one hundred eight million, seven hundred ninety-four thousand, nine hundred thirty-seven".