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4841108794961 is a prime number
BaseRepresentation
bin100011001110010100010…
…0100011110111001010001
3122010210202012021121011022
41012130220210132321101
51113304042322414321
614143550310325225
71006521121542245
oct106345044367121
918123665247138
104841108794961
1115a711478647a
126622a5659815
1329168c76754a
1412a44d220425
1585ddd2a5dab
hex4672891ee51

4841108794961 has 2 divisors, whose sum is σ = 4841108794962. Its totient is φ = 4841108794960.

The previous prime is 4841108794937. The next prime is 4841108794999. The reversal of 4841108794961 is 1694978011484.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2749730049361 + 2091378745600 = 1658231^2 + 1446160^2 .

It is a cyclic number.

It is not a de Polignac number, because 4841108794961 - 218 = 4841108532817 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4841108794894 and 4841108794903.

It is not a weakly prime, because it can be changed into another prime (4841108790961) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2420554397480 + 2420554397481.

It is an arithmetic number, because the mean of its divisors is an integer number (2420554397481).

Almost surely, 24841108794961 is an apocalyptic number.

It is an amenable number.

4841108794961 is a deficient number, since it is larger than the sum of its proper divisors (1).

4841108794961 is an equidigital number, since it uses as much as digits as its factorization.

4841108794961 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13934592, while the sum is 62.

The spelling of 4841108794961 in words is "four trillion, eight hundred forty-one billion, one hundred eight million, seven hundred ninety-four thousand, nine hundred sixty-one".