Base | Representation |
---|---|
bin | 100011010010011010100… |
… | …1011001011010100000111 |
3 | 122011122110120200021111101 |
4 | 1012210311023023110013 |
5 | 1113430104002341214 |
6 | 14152003515120531 |
7 | 1010252203336045 |
oct | 106446513132407 |
9 | 18148416607441 |
10 | 4849910199559 |
11 | 15aa920963a77 |
12 | 663b41143147 |
13 | 292463032969 |
14 | 12aa460db395 |
15 | 86255d04774 |
hex | 469352cb507 |
4849910199559 has 2 divisors, whose sum is σ = 4849910199560. Its totient is φ = 4849910199558.
The previous prime is 4849910199479. The next prime is 4849910199637. The reversal of 4849910199559 is 9559910199484.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4849910199559 - 211 = 4849910197511 is a prime.
It is a super-3 number, since 3×48499101995593 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4849910199491 and 4849910199500.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4849910199859) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2424955099779 + 2424955099780.
It is an arithmetic number, because the mean of its divisors is an integer number (2424955099780).
Almost surely, 24849910199559 is an apocalyptic number.
4849910199559 is a deficient number, since it is larger than the sum of its proper divisors (1).
4849910199559 is an equidigital number, since it uses as much as digits as its factorization.
4849910199559 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 188956800, while the sum is 73.
The spelling of 4849910199559 in words is "four trillion, eight hundred forty-nine billion, nine hundred ten million, one hundred ninety-nine thousand, five hundred fifty-nine".
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