Base | Representation |
---|---|
bin | 101101001100100011… |
… | …011111101010111101 |
3 | 11122021001220022102001 |
4 | 231030203133222331 |
5 | 1243341411412222 |
6 | 34143253102301 |
7 | 3335410544122 |
oct | 551443375275 |
9 | 148231808361 |
10 | 48529013437 |
11 | 196433aa083 |
12 | 94a4327991 |
13 | 4765098688 |
14 | 24c5220749 |
15 | 13e067be27 |
hex | b4c8dfabd |
48529013437 has 2 divisors, whose sum is σ = 48529013438. Its totient is φ = 48529013436.
The previous prime is 48529013387. The next prime is 48529013459. The reversal of 48529013437 is 73431092584.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47884818276 + 644195161 = 218826^2 + 25381^2 .
It is a cyclic number.
It is not a de Polignac number, because 48529013437 - 211 = 48529011389 is a prime.
It is a super-3 number, since 3×485290134373 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48529017437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24264506718 + 24264506719.
It is an arithmetic number, because the mean of its divisors is an integer number (24264506719).
Almost surely, 248529013437 is an apocalyptic number.
It is an amenable number.
48529013437 is a deficient number, since it is larger than the sum of its proper divisors (1).
48529013437 is an equidigital number, since it uses as much as digits as its factorization.
48529013437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760, while the sum is 46.
The spelling of 48529013437 in words is "forty-eight billion, five hundred twenty-nine million, thirteen thousand, four hundred thirty-seven".
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