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48580139481 = 316193379827
BaseRepresentation
bin101101001111100110…
…100001100111011001
311122101122002210011020
4231033212201213121
51243443003430411
634152320553053
73336601241466
oct551746414731
9148348083136
1048580139481
111966a249905
1294b9482789
134772859483
1424cbd2c66d
1513e4dca606
hexb4f9a19d9

48580139481 has 4 divisors (see below), whose sum is σ = 64773519312. Its totient is φ = 32386759652.

The previous prime is 48580139453. The next prime is 48580139497. The reversal of 48580139481 is 18493108584.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 48580139481 - 211 = 48580137433 is a prime.

It is a super-2 number, since 2×485801394812 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (48580139381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8096689911 + ... + 8096689916.

It is an arithmetic number, because the mean of its divisors is an integer number (16193379828).

Almost surely, 248580139481 is an apocalyptic number.

It is an amenable number.

48580139481 is a deficient number, since it is larger than the sum of its proper divisors (16193379831).

48580139481 is a wasteful number, since it uses less digits than its factorization.

48580139481 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16193379830.

The product of its (nonzero) digits is 1105920, while the sum is 51.

The spelling of 48580139481 in words is "forty-eight billion, five hundred eighty million, one hundred thirty-nine thousand, four hundred eighty-one".

Divisors: 1 3 16193379827 48580139481