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48580139381 is a prime number
BaseRepresentation
bin101101001111100110…
…100001100101110101
311122101122002210000112
4231033212201211311
51243443003430011
634152320552405
73336601241264
oct551746414565
9148348083015
1048580139381
111966a249824
1294b9482705
134772859407
1424cbd2c5db
1513e4dca58b
hexb4f9a1975

48580139381 has 2 divisors, whose sum is σ = 48580139382. Its totient is φ = 48580139380.

The previous prime is 48580139329. The next prime is 48580139383. The reversal of 48580139381 is 18393108584.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48580127281 + 12100 = 220409^2 + 110^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-48580139381 is a prime.

It is a super-2 number, since 2×485801393812 (a number of 22 digits) contains 22 as substring.

Together with 48580139383, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (48580139383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24290069690 + 24290069691.

It is an arithmetic number, because the mean of its divisors is an integer number (24290069691).

Almost surely, 248580139381 is an apocalyptic number.

It is an amenable number.

48580139381 is a deficient number, since it is larger than the sum of its proper divisors (1).

48580139381 is an equidigital number, since it uses as much as digits as its factorization.

48580139381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 829440, while the sum is 50.

The spelling of 48580139381 in words is "forty-eight billion, five hundred eighty million, one hundred thirty-nine thousand, three hundred eighty-one".