Base | Representation |
---|---|
bin | 110111001111000011001011… |
… | …0000100011110110000101011 |
3 | 2100201021010211200222122201212 |
4 | 1232132012112010132300223 |
5 | 1002140210443342412122 |
6 | 4441154004523103335 |
7 | 204223520660526626 |
oct | 15636062604366053 |
9 | 2321233750878655 |
10 | 485853513247787 |
11 | 130898355065103 |
12 | 465a97ba671b4b |
13 | 17b13a35cb7b49 |
14 | 87d9615086dbd |
15 | 3b28271597ce2 |
hex | 1b9e19611ec2b |
485853513247787 has 2 divisors, whose sum is σ = 485853513247788. Its totient is φ = 485853513247786.
The previous prime is 485853513247703. The next prime is 485853513247799. The reversal of 485853513247787 is 787742315358584.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 485853513247787 - 210 = 485853513246763 is a prime.
It is not a weakly prime, because it can be changed into another prime (485853513237787) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242926756623893 + 242926756623894.
It is an arithmetic number, because the mean of its divisors is an integer number (242926756623894).
Almost surely, 2485853513247787 is an apocalyptic number.
485853513247787 is a deficient number, since it is larger than the sum of its proper divisors (1).
485853513247787 is an equidigital number, since it uses as much as digits as its factorization.
485853513247787 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6322176000, while the sum is 77.
The spelling of 485853513247787 in words is "four hundred eighty-five trillion, eight hundred fifty-three billion, five hundred thirteen million, two hundred forty-seven thousand, seven hundred eighty-seven".
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