Base | Representation |
---|---|
bin | 10110000110000100100011… |
… | …10011001011001110001111 |
3 | 20101000212211122221210020021 |
4 | 23003002101303023032033 |
5 | 22332022403214221413 |
6 | 251200340225203011 |
7 | 13143206014106665 |
oct | 1303022163131617 |
9 | 211025748853207 |
10 | 48587116163983 |
11 | 14532753458141 |
12 | 5548612a90467 |
13 | 211598c82a2c7 |
14 | bdd8b3c70c35 |
15 | 593ce089718d |
hex | 2c3091ccb38f |
48587116163983 has 2 divisors, whose sum is σ = 48587116163984. Its totient is φ = 48587116163982.
The previous prime is 48587116163923. The next prime is 48587116164007. The reversal of 48587116163983 is 38936161178584.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 48587116163983 - 29 = 48587116163471 is a prime.
It is a super-3 number, since 3×485871161639833 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48587116163923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24293558081991 + 24293558081992.
It is an arithmetic number, because the mean of its divisors is an integer number (24293558081992).
Almost surely, 248587116163983 is an apocalyptic number.
48587116163983 is a deficient number, since it is larger than the sum of its proper divisors (1).
48587116163983 is an equidigital number, since it uses as much as digits as its factorization.
48587116163983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 209018880, while the sum is 70.
The spelling of 48587116163983 in words is "forty-eight trillion, five hundred eighty-seven billion, one hundred sixteen million, one hundred sixty-three thousand, nine hundred eighty-three".
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