Search a number
-
+
487284761317 is a prime number
BaseRepresentation
bin1110001011101000110…
…11110110001011100101
31201120202201020122212111
413011310123312023211
530440424344330232
61011504443321021
750130241062544
oct7056433661345
91646681218774
10487284761317
111787245a9482
127a532820171
1336c48a6c9c3
141982862215b
15ca1e6d0047
hex71746f62e5

487284761317 has 2 divisors, whose sum is σ = 487284761318. Its totient is φ = 487284761316.

The previous prime is 487284761311. The next prime is 487284761371. The reversal of 487284761317 is 713167482784.

Together with next prime (487284761371) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 484853186596 + 2431574721 = 696314^2 + 49311^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-487284761317 is a prime.

It is a super-4 number, since 4×4872847613174 (a number of 48 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (487284761311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 243642380658 + 243642380659.

It is an arithmetic number, because the mean of its divisors is an integer number (243642380659).

Almost surely, 2487284761317 is an apocalyptic number.

It is an amenable number.

487284761317 is a deficient number, since it is larger than the sum of its proper divisors (1).

487284761317 is an equidigital number, since it uses as much as digits as its factorization.

487284761317 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12644352, while the sum is 58.

The spelling of 487284761317 in words is "four hundred eighty-seven billion, two hundred eighty-four million, seven hundred sixty-one thousand, three hundred seventeen".