Base | Representation |
---|---|
bin | 110111011001101011000011… |
… | …0001000010000000010101111 |
3 | 2100220102201102002220012011101 |
4 | 1232303112012020100002233 |
5 | 1002333121104334300023 |
6 | 4444232425225303531 |
7 | 204434145450123643 |
oct | 15663260610200257 |
9 | 2326381362805141 |
10 | 487313534681263 |
11 | 1313005670a9774 |
12 | 467a4764934ba7 |
13 | 17bbb613914914 |
14 | 884a15ad24c23 |
15 | 3b51223c911ad |
hex | 1bb35862100af |
487313534681263 has 2 divisors, whose sum is σ = 487313534681264. Its totient is φ = 487313534681262.
The previous prime is 487313534681251. The next prime is 487313534681383. The reversal of 487313534681263 is 362186435313784.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 487313534681263 - 29 = 487313534680751 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 487313534681195 and 487313534681204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (487313534682263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 243656767340631 + 243656767340632.
It is an arithmetic number, because the mean of its divisors is an integer number (243656767340632).
Almost surely, 2487313534681263 is an apocalyptic number.
487313534681263 is a deficient number, since it is larger than the sum of its proper divisors (1).
487313534681263 is an equidigital number, since it uses as much as digits as its factorization.
487313534681263 is an evil number, because the sum of its binary digits is even.
The product of its digits is 209018880, while the sum is 64.
The spelling of 487313534681263 in words is "four hundred eighty-seven trillion, three hundred thirteen billion, five hundred thirty-four million, six hundred eighty-one thousand, two hundred sixty-three".
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