Search a number
-
+
4890203348957 is a prime number
BaseRepresentation
bin100011100101001011011…
…0101010101111111011101
3122022111110200100100100222
41013022112311111333131
51120110114024131312
614222310045131125
71013206540424603
oct107122665257735
918274420310328
104890203348957
111615a18337543
1266b907259aa5
132961b4a54ab4
1412c9895b7873
15873133e5672
hex47296d55fdd

4890203348957 has 2 divisors, whose sum is σ = 4890203348958. Its totient is φ = 4890203348956.

The previous prime is 4890203348941. The next prime is 4890203348977. The reversal of 4890203348957 is 7598433020984.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3081127238596 + 1809076110361 = 1755314^2 + 1345019^2 .

It is a cyclic number.

It is not a de Polignac number, because 4890203348957 - 24 = 4890203348941 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4890203348957.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4890203348917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2445101674478 + 2445101674479.

It is an arithmetic number, because the mean of its divisors is an integer number (2445101674479).

Almost surely, 24890203348957 is an apocalyptic number.

It is an amenable number.

4890203348957 is a deficient number, since it is larger than the sum of its proper divisors (1).

4890203348957 is an equidigital number, since it uses as much as digits as its factorization.

4890203348957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 52254720, while the sum is 62.

The spelling of 4890203348957 in words is "four trillion, eight hundred ninety billion, two hundred three million, three hundred forty-eight thousand, nine hundred fifty-seven".