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48903 = 316301
BaseRepresentation
bin1011111100000111
32111002020
423330013
53031103
61014223
7262401
oct137407
974066
1048903
1133818
1224373
131934a
1413b71
15e753
hexbf07

48903 has 4 divisors (see below), whose sum is σ = 65208. Its totient is φ = 32600.

The previous prime is 48889. The next prime is 48907. The reversal of 48903 is 30984.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 48903 - 25 = 48871 is a prime.

It is a D-number.

It is a nialpdrome in base 15.

It is a congruent number.

It is an inconsummate number, since it does not exist a number n which divided by its sum of digits gives 48903.

It is not an unprimeable number, because it can be changed into a prime (48907) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8148 + ... + 8153.

It is an arithmetic number, because the mean of its divisors is an integer number (16302).

248903 is an apocalyptic number.

48903 is a deficient number, since it is larger than the sum of its proper divisors (16305).

48903 is a wasteful number, since it uses less digits than its factorization.

48903 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16304.

The product of its (nonzero) digits is 864, while the sum is 24.

The square root of 48903 is about 221.1402270054. The cubic root of 48903 is about 36.5688947103.

The spelling of 48903 in words is "forty-eight thousand, nine hundred three".

Divisors: 1 3 16301 48903