Base | Representation |
---|---|
bin | 101101100011100110… |
… | …000000101111000111 |
3 | 11200021000020100200201 |
4 | 231203212000233013 |
5 | 1300134340033002 |
6 | 34245501551331 |
7 | 3351113210254 |
oct | 554346005707 |
9 | 150230210621 |
10 | 48915549127 |
11 | 19821609065 |
12 | 9591875547 |
13 | 47c71a4613 |
14 | 25206bc42b |
15 | 1414581087 |
hex | b63980bc7 |
48915549127 has 2 divisors, whose sum is σ = 48915549128. Its totient is φ = 48915549126.
The previous prime is 48915549119. The next prime is 48915549139. The reversal of 48915549127 is 72194551984.
48915549127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 48915549127 - 23 = 48915549119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48915579127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24457774563 + 24457774564.
It is an arithmetic number, because the mean of its divisors is an integer number (24457774564).
Almost surely, 248915549127 is an apocalyptic number.
48915549127 is a deficient number, since it is larger than the sum of its proper divisors (1).
48915549127 is an equidigital number, since it uses as much as digits as its factorization.
48915549127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3628800, while the sum is 55.
The spelling of 48915549127 in words is "forty-eight billion, nine hundred fifteen million, five hundred forty-nine thousand, one hundred twenty-seven".
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