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4891952170981 = 15313195265951
BaseRepresentation
bin100011100101111111100…
…0100100100011111100101
3122022122222120001201012001
41013023333010210133211
51120122204223432411
614223155400325301
71013301064240231
oct107137704443745
918278876051161
104891952170981
1116167355163a7
12670114a73831
13296403166525
1412cab396b5c1
15873b6bdedc1
hex472ff1247e5

4891952170981 has 4 divisors (see below), whose sum is σ = 4895147438464. Its totient is φ = 4888756903500.

The previous prime is 4891952170949. The next prime is 4891952170993. The reversal of 4891952170981 is 1890712591984.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4891952170981 - 25 = 4891952170949 is a prime.

It is a super-2 number, since 2×48919521709812 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4891952170181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1597631445 + ... + 1597634506.

It is an arithmetic number, because the mean of its divisors is an integer number (1223786859616).

Almost surely, 24891952170981 is an apocalyptic number.

It is an amenable number.

4891952170981 is a deficient number, since it is larger than the sum of its proper divisors (3195267483).

4891952170981 is a wasteful number, since it uses less digits than its factorization.

4891952170981 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3195267482.

The product of its (nonzero) digits is 13063680, while the sum is 64.

The spelling of 4891952170981 in words is "four trillion, eight hundred ninety-one billion, nine hundred fifty-two million, one hundred seventy thousand, nine hundred eighty-one".

Divisors: 1 1531 3195265951 4891952170981