Base | Representation |
---|---|
bin | 101101100100000111… |
… | …010010000111110101 |
3 | 11200021121122110222111 |
4 | 231210013102013311 |
5 | 1300144103133333 |
6 | 34250412531021 |
7 | 3351250304605 |
oct | 554407220765 |
9 | 150247573874 |
10 | 48924271093 |
11 | 19826525aa5 |
12 | 9594780a71 |
13 | 47c8c39549 |
14 | 252190cc05 |
15 | 14152054cd |
hex | b641d21f5 |
48924271093 has 2 divisors, whose sum is σ = 48924271094. Its totient is φ = 48924271092.
The previous prime is 48924271073. The next prime is 48924271171. The reversal of 48924271093 is 39017242984.
48924271093 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 48361727569 + 562543524 = 219913^2 + 23718^2 .
It is a cyclic number.
It is not a de Polignac number, because 48924271093 - 29 = 48924270581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48924271043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24462135546 + 24462135547.
It is an arithmetic number, because the mean of its divisors is an integer number (24462135547).
Almost surely, 248924271093 is an apocalyptic number.
It is an amenable number.
48924271093 is a deficient number, since it is larger than the sum of its proper divisors (1).
48924271093 is an equidigital number, since it uses as much as digits as its factorization.
48924271093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 49.
The spelling of 48924271093 in words is "forty-eight billion, nine hundred twenty-four million, two hundred seventy-one thousand, ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •