Base | Representation |
---|---|
bin | 110111101010000101000100… |
… | …0011101011011010110010111 |
3 | 2101012102021200202022000210221 |
4 | 1233110022020131123112113 |
5 | 1003132042121443224211 |
6 | 4453120344352255211 |
7 | 205056103056623425 |
oct | 15724121035332627 |
9 | 2335367622260727 |
10 | 489568431617431 |
11 | 131a9a895697391 |
12 | 46aa9785241507 |
13 | 1802314991c52a |
14 | 88c734a6da115 |
15 | 3b8ebe9931c71 |
hex | 1bd428875b597 |
489568431617431 has 2 divisors, whose sum is σ = 489568431617432. Its totient is φ = 489568431617430.
The previous prime is 489568431617357. The next prime is 489568431617437. The reversal of 489568431617431 is 134716134865984.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 489568431617431 - 221 = 489568429520279 is a prime.
It is a super-2 number, since 2×4895684316174312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (489568431617437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 244784215808715 + 244784215808716.
It is an arithmetic number, because the mean of its divisors is an integer number (244784215808716).
Almost surely, 2489568431617431 is an apocalyptic number.
489568431617431 is a deficient number, since it is larger than the sum of its proper divisors (1).
489568431617431 is an equidigital number, since it uses as much as digits as its factorization.
489568431617431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 418037760, while the sum is 70.
The spelling of 489568431617431 in words is "four hundred eighty-nine trillion, five hundred sixty-eight billion, four hundred thirty-one million, six hundred seventeen thousand, four hundred thirty-one".
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