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49020485749 is a prime number
BaseRepresentation
bin101101101001110110…
…010100000001110101
311200112022200200200021
4231221312110001311
51300343221020444
634304131045141
73353526153034
oct555166240165
9150468620607
1049020485749
1119875871544
129600a407b1
134812b560b1
1425305d671b
15141d8ad584
hexb69d94075

49020485749 has 2 divisors, whose sum is σ = 49020485750. Its totient is φ = 49020485748.

The previous prime is 49020485737. The next prime is 49020485803. The reversal of 49020485749 is 94758402094.

49020485749 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 36554763249 + 12465722500 = 191193^2 + 111650^2 .

It is a cyclic number.

It is not a de Polignac number, because 49020485749 - 29 = 49020485237 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 49020485696 and 49020485705.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49020480749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24510242874 + 24510242875.

It is an arithmetic number, because the mean of its divisors is an integer number (24510242875).

Almost surely, 249020485749 is an apocalyptic number.

It is an amenable number.

49020485749 is a deficient number, since it is larger than the sum of its proper divisors (1).

49020485749 is an equidigital number, since it uses as much as digits as its factorization.

49020485749 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2903040, while the sum is 52.

The spelling of 49020485749 in words is "forty-nine billion, twenty million, four hundred eighty-five thousand, seven hundred forty-nine".