Base | Representation |
---|---|
bin | 10110010010101110000001… |
… | …00111010101111100100111 |
3 | 20102120102120002111001200111 |
4 | 23021113000213111330213 |
5 | 22411132411440210411 |
6 | 252132131025153451 |
7 | 13216462154525266 |
oct | 1311270047257447 |
9 | 212512502431614 |
10 | 49021693288231 |
11 | 1468aa8a960784 |
12 | 55b8895a8b887 |
13 | 214795889b681 |
14 | c1693c3025dd |
15 | 5a0277b3e721 |
hex | 2c95c09d5f27 |
49021693288231 has 2 divisors, whose sum is σ = 49021693288232. Its totient is φ = 49021693288230.
The previous prime is 49021693288163. The next prime is 49021693288237. The reversal of 49021693288231 is 13288239612094.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49021693288231 - 29 = 49021693287719 is a prime.
It is a super-2 number, since 2×490216932882312 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49021693288237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24510846644115 + 24510846644116.
It is an arithmetic number, because the mean of its divisors is an integer number (24510846644116).
Almost surely, 249021693288231 is an apocalyptic number.
49021693288231 is a deficient number, since it is larger than the sum of its proper divisors (1).
49021693288231 is an equidigital number, since it uses as much as digits as its factorization.
49021693288231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8957952, while the sum is 58.
The spelling of 49021693288231 in words is "forty-nine trillion, twenty-one billion, six hundred ninety-three million, two hundred eighty-eight thousand, two hundred thirty-one".
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