490313531 has 2 divisors, whose sum is σ = 490313532. Its totient is φ = 490313530.

The previous prime is 490313521. The next prime is 490313533. The reversal of 490313531 is 135313094.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-490313531 is a prime.

It is a super-2 number, since 2×490313531² = 480814717363375922, which contains 22 as substring.

Together with 490313533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 490313494 and 490313503.

It is not a weakly prime, because it can be changed into another prime (490313533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245156765 + 245156766.

It is an arithmetic number, because the mean of its divisors is an integer number (245156766).

Almost surely, 2^490313531 is an apocalyptic number.

490313531 is a deficient number, since it is larger than the sum of its proper divisors (1).

490313531 is an equidigital number, since it uses as much as digits as its factorization.

490313531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4860, while the sum is 29.

The square root of 490313531 is about 22143.0244320870. The cubic root of 490313531 is about 788.5416298042.

The spelling of 490313531 in words is "four hundred ninety million, three hundred thirteen thousand, five hundred thirty-one".