Base | Representation |
---|---|
bin | 1110010001010011110… |
… | …11110100100010101111 |
3 | 1201212121221001122011012 |
4 | 13020221323310202233 |
5 | 31013143413204221 |
6 | 1013130541415435 |
7 | 50265554460623 |
oct | 7105173644257 |
9 | 1655557048135 |
10 | 490329819311 |
11 | 179a47444632 |
12 | 7b04256a57b |
13 | 3731289c077 |
14 | 19a36bd7183 |
15 | cb4bbc465b |
hex | 7229ef48af |
490329819311 has 2 divisors, whose sum is σ = 490329819312. Its totient is φ = 490329819310.
The previous prime is 490329819283. The next prime is 490329819341. The reversal of 490329819311 is 113918923094.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 490329819311 - 222 = 490325625007 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 490329819311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (490329819341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245164909655 + 245164909656.
It is an arithmetic number, because the mean of its divisors is an integer number (245164909656).
Almost surely, 2490329819311 is an apocalyptic number.
490329819311 is a deficient number, since it is larger than the sum of its proper divisors (1).
490329819311 is an equidigital number, since it uses as much as digits as its factorization.
490329819311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 419904, while the sum is 50.
The spelling of 490329819311 in words is "four hundred ninety billion, three hundred twenty-nine million, eight hundred nineteen thousand, three hundred eleven".
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