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4906103370127 is a prime number
BaseRepresentation
bin100011101100100101010…
…0011000111000110001111
3122101000111210001002222221
41013121022203013012033
51120340144430321002
614233455513520211
71014311546401501
oct107311243070617
918330453032887
104906103370127
1116217374a5803
12672a04113067
13297849ba404b
1412d657161d71
158794423cc37
hex4764a8c718f

4906103370127 has 2 divisors, whose sum is σ = 4906103370128. Its totient is φ = 4906103370126.

The previous prime is 4906103370059. The next prime is 4906103370143. The reversal of 4906103370127 is 7210733016094.

4906103370127 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4906103370127 is a prime.

It is a super-2 number, since 2×49061033701272 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4906103374127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2453051685063 + 2453051685064.

It is an arithmetic number, because the mean of its divisors is an integer number (2453051685064).

Almost surely, 24906103370127 is an apocalyptic number.

4906103370127 is a deficient number, since it is larger than the sum of its proper divisors (1).

4906103370127 is an equidigital number, since it uses as much as digits as its factorization.

4906103370127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 190512, while the sum is 43.

The spelling of 4906103370127 in words is "four trillion, nine hundred six billion, one hundred three million, three hundred seventy thousand, one hundred twenty-seven".