Base | Representation |
---|---|
bin | 101101101101000010… |
… | …110000010110011101 |
3 | 11200200001112111222102 |
4 | 231231002300112131 |
5 | 1301000431013013 |
6 | 34313323454445 |
7 | 3355046535002 |
oct | 555502602635 |
9 | 150601474872 |
10 | 49074079133 |
11 | 198a3046aa2 |
12 | 9616987425 |
13 | 4820c9bc61 |
14 | 25377878a9 |
15 | 1423447d58 |
hex | b6d0b059d |
49074079133 has 2 divisors, whose sum is σ = 49074079134. Its totient is φ = 49074079132.
The previous prime is 49074079091. The next prime is 49074079157. The reversal of 49074079133 is 33197047094.
49074079133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38803878169 + 10270200964 = 196987^2 + 101342^2 .
It is a cyclic number.
It is not a de Polignac number, because 49074079133 - 214 = 49074062749 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49074079633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24537039566 + 24537039567.
It is an arithmetic number, because the mean of its divisors is an integer number (24537039567).
Almost surely, 249074079133 is an apocalyptic number.
It is an amenable number.
49074079133 is a deficient number, since it is larger than the sum of its proper divisors (1).
49074079133 is an equidigital number, since it uses as much as digits as its factorization.
49074079133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 571536, while the sum is 47.
The spelling of 49074079133 in words is "forty-nine billion, seventy-four million, seventy-nine thousand, one hundred thirty-three".
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