Base | Representation |
---|---|
bin | 1110010010001101000… |
… | …01011000011100001011 |
3 | 1201220212100112021012201 |
4 | 13021012201120130023 |
5 | 31020134203141343 |
6 | 1013250313221031 |
7 | 50313500205106 |
oct | 7110641303413 |
9 | 1656770467181 |
10 | 490809427723 |
11 | 17a17314351a |
12 | 7b157101777 |
13 | 3738b064724 |
14 | 19a807a173d |
15 | cb78d6094d |
hex | 724685870b |
490809427723 has 2 divisors, whose sum is σ = 490809427724. Its totient is φ = 490809427722.
The previous prime is 490809427709. The next prime is 490809427729. The reversal of 490809427723 is 327724908094.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 490809427723 - 237 = 353370474251 is a prime.
It is a super-3 number, since 3×4908094277233 (a number of 36 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (490809427729) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245404713861 + 245404713862.
It is an arithmetic number, because the mean of its divisors is an integer number (245404713862).
Almost surely, 2490809427723 is an apocalyptic number.
490809427723 is a deficient number, since it is larger than the sum of its proper divisors (1).
490809427723 is an equidigital number, since it uses as much as digits as its factorization.
490809427723 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6096384, while the sum is 55.
The spelling of 490809427723 in words is "four hundred ninety billion, eight hundred nine million, four hundred twenty-seven thousand, seven hundred twenty-three".
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