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49098048999941 is a prime number
BaseRepresentation
bin10110010100111100001111…
…10001010001001000000101
320102211201122110020002222002
423022132013301101020011
522413410301020444231
6252231155441115045
713225134265416554
oct1312360761211005
9212751573202862
1049098048999941
111470a40274a057
12560b645328a85
132151c069b7986
14c1a50307dd9b
155a22461ee0cb
hex2ca787c51205

49098048999941 has 2 divisors, whose sum is σ = 49098048999942. Its totient is φ = 49098048999940.

The previous prime is 49098048999899. The next prime is 49098049000001. The reversal of 49098048999941 is 14999984089094.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 44882094348100 + 4215954651841 = 6699410^2 + 2053279^2 .

It is a cyclic number.

It is not a de Polignac number, because 49098048999941 - 26 = 49098048999877 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 49098048999941.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49098048909941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24549024499970 + 24549024499971.

It is an arithmetic number, because the mean of its divisors is an integer number (24549024499971).

Almost surely, 249098048999941 is an apocalyptic number.

It is an amenable number.

49098048999941 is a deficient number, since it is larger than the sum of its proper divisors (1).

49098048999941 is an equidigital number, since it uses as much as digits as its factorization.

49098048999941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2176782336, while the sum is 83.

The spelling of 49098048999941 in words is "forty-nine trillion, ninety-eight billion, forty-eight million, nine hundred ninety-nine thousand, nine hundred forty-one".