49108313526977 has 2 divisors, whose sum is σ = 49108313526978. Its totient is φ = 49108313526976.

The previous prime is 49108313526959. The next prime is 49108313526991. The reversal of 49108313526977 is 77962531380194.

49108313526977 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44810117969296 + 4298195557681 = 6694036^2 + 2073209^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-49108313526977 is a prime.

It is a super-3 number, since 3×49108313526977³ (a number of 42 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (49108313526917) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24554156763488 + 24554156763489.

It is an arithmetic number, because the mean of its divisors is an integer number (24554156763489).

It is a 2-persistent number, because it is pandigital, and so is 2⋅49108313526977 = 98216627053954, but 3⋅49108313526977 = 147324940580931 is not.

Almost surely, 2^{49108313526977} is an apocalyptic number.

It is an amenable number.

49108313526977 is a deficient number, since it is larger than the sum of its proper divisors (1).

49108313526977 is an equidigital number, since it uses as much as digits as its factorization.

49108313526977 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 68584320, while the sum is 65.

The spelling of 49108313526977 in words is "forty-nine trillion, one hundred eight billion, three hundred thirteen million, five hundred twenty-six thousand, nine hundred seventy-seven".