Base | Representation |
---|---|
bin | 1001001001011110… |
… | …10001010101100101 |
3 | 110200021112212100000 |
4 | 10210233101111211 |
5 | 40024300320403 |
6 | 2131203011513 |
7 | 232464456111 |
oct | 44457212545 |
9 | 13607485300 |
10 | 4911338853 |
11 | 20a0360633 |
12 | b50969b99 |
13 | 603688185 |
14 | 3483c2741 |
15 | 1db2917a3 |
hex | 124bd1565 |
4911338853 has 24 divisors (see below), whose sum is σ = 7361172000. Its totient is φ = 3272326128.
The previous prime is 4911338851. The next prime is 4911338857. The reversal of 4911338853 is 3588331194.
4911338853 is a `hidden beast` number, since 491 + 1 + 33 + 88 + 53 = 666.
It is not a de Polignac number, because 4911338853 - 21 = 4911338851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4911338799 and 4911338808.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4911338851) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 505243 + ... + 514871.
It is an arithmetic number, because the mean of its divisors is an integer number (306715500).
Almost surely, 24911338853 is an apocalyptic number.
It is an amenable number.
4911338853 is a deficient number, since it is larger than the sum of its proper divisors (2449833147).
4911338853 is an equidigital number, since it uses as much as digits as its factorization.
4911338853 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11743 (or 11731 counting only the distinct ones).
The product of its digits is 311040, while the sum is 45.
The square root of 4911338853 is about 70080.9450064709. The cubic root of 4911338853 is about 1699.8083812857.
The spelling of 4911338853 in words is "four billion, nine hundred eleven million, three hundred thirty-eight thousand, eight hundred fifty-three".
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