Base | Representation |
---|---|
bin | 10110010101110010001111… |
… | …11111111111111111110011 |
3 | 20102221111111011020012100001 |
4 | 23022321013333333333303 |
5 | 22414344141214004222 |
6 | 252252352530210431 |
7 | 13230211642056313 |
oct | 1312710777777763 |
9 | 212844434205301 |
10 | 49127043891187 |
11 | 1472073159aa99 |
12 | 5615197723a17 |
13 | 2154877a74462 |
14 | c1ba93c0b443 |
15 | 5a2d91987e27 |
hex | 2cae47fffff3 |
49127043891187 has 2 divisors, whose sum is σ = 49127043891188. Its totient is φ = 49127043891186.
The previous prime is 49127043891157. The next prime is 49127043891227. The reversal of 49127043891187 is 78119834072194.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49127043891187 - 223 = 49127035502579 is a prime.
It is a super-2 number, since 2×491270438911872 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (49127043891157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24563521945593 + 24563521945594.
It is an arithmetic number, because the mean of its divisors is an integer number (24563521945594).
Almost surely, 249127043891187 is an apocalyptic number.
49127043891187 is a deficient number, since it is larger than the sum of its proper divisors (1).
49127043891187 is an equidigital number, since it uses as much as digits as its factorization.
49127043891187 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24385536, while the sum is 64.
The spelling of 49127043891187 in words is "forty-nine trillion, one hundred twenty-seven billion, forty-three million, eight hundred ninety-one thousand, one hundred eighty-seven".
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