Base | Representation |
---|---|
bin | 10110010101110010010000… |
… | …00000000000000000011011 |
3 | 20102221111111011020012101112 |
4 | 23022321020000000000123 |
5 | 22414344141214004402 |
6 | 252252352530210535 |
7 | 13230211642056401 |
oct | 1312711000000033 |
9 | 212844434205345 |
10 | 49127043891227 |
11 | 147207315a0025 |
12 | 5615197723a4b |
13 | 2154877a74493 |
14 | c1ba93c0b471 |
15 | 5a2d91987e52 |
hex | 2cae4800001b |
49127043891227 has 2 divisors, whose sum is σ = 49127043891228. Its totient is φ = 49127043891226.
The previous prime is 49127043891187. The next prime is 49127043891229. The reversal of 49127043891227 is 72219834072194.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49127043891227 - 210 = 49127043890203 is a prime.
Together with 49127043891229, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (49127043891229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24563521945613 + 24563521945614.
It is an arithmetic number, because the mean of its divisors is an integer number (24563521945614).
Almost surely, 249127043891227 is an apocalyptic number.
49127043891227 is a deficient number, since it is larger than the sum of its proper divisors (1).
49127043891227 is an equidigital number, since it uses as much as digits as its factorization.
49127043891227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12192768, while the sum is 59.
The spelling of 49127043891227 in words is "forty-nine trillion, one hundred twenty-seven billion, forty-three million, eight hundred ninety-one thousand, two hundred twenty-seven".
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