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49127114400 = 253527131911839
BaseRepresentation
bin101101110000001101…
…000100011010100000
311200210202022222200120
4231300031010122200
51301103020130100
634322500320240
73356262403530
oct556015043240
9150722288616
1049127114400
111991aa801a1
1296306a3080
13482bc7aa80
1425408314c0
151427e220a0
hexb703446a0

49127114400 has 576 divisors, whose sum is σ = 207186739200. Its totient is φ = 9818910720.

The previous prime is 49127114389. The next prime is 49127114447. The reversal of 49127114400 is 441172194.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4143681 + ... + 4155519.

It is an arithmetic number, because the mean of its divisors is an integer number (359699200).

Almost surely, 249127114400 is an apocalyptic number.

49127114400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 49127114400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (103593369600).

49127114400 is an abundant number, since it is smaller than the sum of its proper divisors (158059624800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

49127114400 is a wasteful number, since it uses less digits than its factorization.

49127114400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11901 (or 11888 counting only the distinct ones).

The product of its (nonzero) digits is 8064, while the sum is 33.

Adding to 49127114400 its reverse (441172194), we get a palindrome (49568286594).

The spelling of 49127114400 in words is "forty-nine billion, one hundred twenty-seven million, one hundred fourteen thousand, four hundred".