491301313432031 has 4 divisors (see below), whose sum is σ = 491303515782912. Its totient is φ = 491299111081152.

The previous prime is 491301313431989. The next prime is 491301313432037. The reversal of 491301313432031 is 130234313103194.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-491301313432031 is a prime.

It is a super-2 number, since 2×491301313432031² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (491301313432037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1100840786 + ... + 1101286991.

It is an arithmetic number, because the mean of its divisors is an integer number (122825878945728).

Almost surely, 2^{491301313432031} is an apocalyptic number.

491301313432031 is a deficient number, since it is larger than the sum of its proper divisors (2202350881).

491301313432031 is a wasteful number, since it uses less digits than its factorization.

491301313432031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2202350880.

The product of its (nonzero) digits is 69984, while the sum is 38.

The spelling of 491301313432031 in words is "four hundred ninety-one trillion, three hundred one billion, three hundred thirteen million, four hundred thirty-two thousand, thirty-one".