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49131529247 is a prime number
BaseRepresentation
bin101101110000011101…
…111010010000011111
311200211001122021201102
4231300131322100133
51301110132413442
634323135103315
73356345052023
oct556035722037
9150731567642
1049131529247
1119922516129
129632071b3b
13482cb653c8
142541260383
1514284e5232
hexb7077a41f

49131529247 has 2 divisors, whose sum is σ = 49131529248. Its totient is φ = 49131529246.

The previous prime is 49131529217. The next prime is 49131529261. The reversal of 49131529247 is 74292513194.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 49131529247 - 212 = 49131525151 is a prime.

It is a super-2 number, since 2×491315292472 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49131529207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24565764623 + 24565764624.

It is an arithmetic number, because the mean of its divisors is an integer number (24565764624).

Almost surely, 249131529247 is an apocalyptic number.

49131529247 is a deficient number, since it is larger than the sum of its proper divisors (1).

49131529247 is an equidigital number, since it uses as much as digits as its factorization.

49131529247 is an evil number, because the sum of its binary digits is even.

The product of its digits is 544320, while the sum is 47.

The spelling of 49131529247 in words is "forty-nine billion, one hundred thirty-one million, five hundred twenty-nine thousand, two hundred forty-seven".