Base | Representation |
---|---|
bin | 1110010011001001011… |
… | …10000110010000010111 |
3 | 1201222011122212202011122 |
4 | 13021210232012100113 |
5 | 31022203403440331 |
6 | 1013412452354155 |
7 | 50332161516323 |
oct | 7114456062027 |
9 | 1658148782148 |
10 | 491316077591 |
11 | 17a403132019 |
12 | 7b27891595b |
13 | 3743c007551 |
14 | 19acbba8983 |
15 | cba858e17b |
hex | 7264b86417 |
491316077591 has 2 divisors, whose sum is σ = 491316077592. Its totient is φ = 491316077590.
The previous prime is 491316077507. The next prime is 491316077627. The reversal of 491316077591 is 195770613194.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-491316077591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (491316077491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245658038795 + 245658038796.
It is an arithmetic number, because the mean of its divisors is an integer number (245658038796).
Almost surely, 2491316077591 is an apocalyptic number.
491316077591 is a deficient number, since it is larger than the sum of its proper divisors (1).
491316077591 is an equidigital number, since it uses as much as digits as its factorization.
491316077591 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1428840, while the sum is 53.
The spelling of 491316077591 in words is "four hundred ninety-one billion, three hundred sixteen million, seventy-seven thousand, five hundred ninety-one".
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