Base | Representation |
---|---|
bin | 101101110000100101… |
… | …001011000101100111 |
3 | 11200211012020000102212 |
4 | 231300211023011213 |
5 | 1301111124330231 |
6 | 34323243554035 |
7 | 3356400201623 |
oct | 556045130547 |
9 | 150735200385 |
10 | 49133433191 |
11 | 199235a6637 |
12 | 963282b91b |
13 | 4830380bbb |
14 | 25415d8183 |
15 | 142876e42b |
hex | b7094b167 |
49133433191 has 2 divisors, whose sum is σ = 49133433192. Its totient is φ = 49133433190.
The previous prime is 49133433187. The next prime is 49133433197. The reversal of 49133433191 is 19133433194.
49133433191 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49133433191 - 22 = 49133433187 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49133433197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24566716595 + 24566716596.
It is an arithmetic number, because the mean of its divisors is an integer number (24566716596).
Almost surely, 249133433191 is an apocalyptic number.
49133433191 is a deficient number, since it is larger than the sum of its proper divisors (1).
49133433191 is an equidigital number, since it uses as much as digits as its factorization.
49133433191 is an evil number, because the sum of its binary digits is even.
The product of its digits is 104976, while the sum is 41.
The spelling of 49133433191 in words is "forty-nine billion, one hundred thirty-three million, four hundred thirty-three thousand, one hundred ninety-one".
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