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4913361293 is a prime number
BaseRepresentation
bin1001001001101101…
…11111000110001101
3110200102100121121012
410210312333012031
540030310030133
62131314215005
7232520611331
oct44466770615
913612317535
104913361293
1120a1512075
12b51584465
13603c15899
1434878b7c1
151db540b48
hex124dbf18d

4913361293 has 2 divisors, whose sum is σ = 4913361294. Its totient is φ = 4913361292.

The previous prime is 4913361227. The next prime is 4913361319. The reversal of 4913361293 is 3921633194.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4866876169 + 46485124 = 69763^2 + 6818^2 .

It is a cyclic number.

It is not a de Polignac number, because 4913361293 - 216 = 4913295757 is a prime.

It is a super-2 number, since 2×49133612932 = 48282238391101263698, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4913361293.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4913361493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2456680646 + 2456680647.

It is an arithmetic number, because the mean of its divisors is an integer number (2456680647).

Almost surely, 24913361293 is an apocalyptic number.

It is an amenable number.

4913361293 is a deficient number, since it is larger than the sum of its proper divisors (1).

4913361293 is an equidigital number, since it uses as much as digits as its factorization.

4913361293 is an evil number, because the sum of its binary digits is even.

The product of its digits is 104976, while the sum is 41.

The square root of 4913361293 is about 70095.3728358727. The cubic root of 4913361293 is about 1700.0416706049.

The spelling of 4913361293 in words is "four billion, nine hundred thirteen million, three hundred sixty-one thousand, two hundred ninety-three".