Base | Representation |
---|---|
bin | 1001001001101101… |
… | …11111000110001101 |
3 | 110200102100121121012 |
4 | 10210312333012031 |
5 | 40030310030133 |
6 | 2131314215005 |
7 | 232520611331 |
oct | 44466770615 |
9 | 13612317535 |
10 | 4913361293 |
11 | 20a1512075 |
12 | b51584465 |
13 | 603c15899 |
14 | 34878b7c1 |
15 | 1db540b48 |
hex | 124dbf18d |
4913361293 has 2 divisors, whose sum is σ = 4913361294. Its totient is φ = 4913361292.
The previous prime is 4913361227. The next prime is 4913361319. The reversal of 4913361293 is 3921633194.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4866876169 + 46485124 = 69763^2 + 6818^2 .
It is a cyclic number.
It is not a de Polignac number, because 4913361293 - 216 = 4913295757 is a prime.
It is a super-2 number, since 2×49133612932 = 48282238391101263698, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 4913361293.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4913361493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2456680646 + 2456680647.
It is an arithmetic number, because the mean of its divisors is an integer number (2456680647).
Almost surely, 24913361293 is an apocalyptic number.
It is an amenable number.
4913361293 is a deficient number, since it is larger than the sum of its proper divisors (1).
4913361293 is an equidigital number, since it uses as much as digits as its factorization.
4913361293 is an evil number, because the sum of its binary digits is even.
The product of its digits is 104976, while the sum is 41.
The square root of 4913361293 is about 70095.3728358727. The cubic root of 4913361293 is about 1700.0416706049.
The spelling of 4913361293 in words is "four billion, nine hundred thirteen million, three hundred sixty-one thousand, two hundred ninety-three".
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