Base | Representation |
---|---|
bin | 100011110000000010101… |
… | …0000010111111100100101 |
3 | 122101201200101222212110101 |
4 | 1013200011100113330211 |
5 | 1121000402333440333 |
6 | 14241124520424101 |
7 | 1014663605251306 |
oct | 107400520277445 |
9 | 18351611885411 |
10 | 4913530765093 |
11 | 16248a9026555 |
12 | 674337618031 |
13 | 2984618c0902 |
14 | 12db5d7747ad |
15 | 87c2b32c67d |
hex | 47805417f25 |
4913530765093 has 2 divisors, whose sum is σ = 4913530765094. Its totient is φ = 4913530765092.
The previous prime is 4913530765043. The next prime is 4913530765111. The reversal of 4913530765093 is 3905670353194.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4845911003649 + 67619761444 = 2201343^2 + 260038^2 .
It is a cyclic number.
It is not a de Polignac number, because 4913530765093 - 221 = 4913528667941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4913530765043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2456765382546 + 2456765382547.
It is an arithmetic number, because the mean of its divisors is an integer number (2456765382547).
Almost surely, 24913530765093 is an apocalyptic number.
It is an amenable number.
4913530765093 is a deficient number, since it is larger than the sum of its proper divisors (1).
4913530765093 is an equidigital number, since it uses as much as digits as its factorization.
4913530765093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9185400, while the sum is 55.
The spelling of 4913530765093 in words is "four trillion, nine hundred thirteen billion, five hundred thirty million, seven hundred sixty-five thousand, ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •