491380433 has 2 divisors, whose sum is σ = 491380434. Its totient is φ = 491380432.

The previous prime is 491380397. The next prime is 491380459. The reversal of 491380433 is 334083194.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 489825424 + 1555009 = 22132^2 + 1247^2 .

It is a cyclic number.

It is not a de Polignac number, because 491380433 - 2⁸ = 491380177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 491380393 and 491380402.

It is not a weakly prime, because it can be changed into another prime (491380133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245690216 + 245690217.

It is an arithmetic number, because the mean of its divisors is an integer number (245690217).

Almost surely, 2^491380433 is an apocalyptic number.

It is an amenable number.

491380433 is a deficient number, since it is larger than the sum of its proper divisors (1).

491380433 is an equidigital number, since it uses as much as digits as its factorization.

491380433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 35.

The square root of 491380433 is about 22167.1024944624. The cubic root of 491380433 is about 789.1131601390.

The spelling of 491380433 in words is "four hundred ninety-one million, three hundred eighty thousand, four hundred thirty-three".