Base | Representation |
---|---|
bin | 10110010110010100101011… |
… | …11100010000010101110001 |
3 | 20110000021012120202000220101 |
4 | 23023022111330100111301 |
5 | 22420200022014322320 |
6 | 252305051225512401 |
7 | 13231435040236453 |
oct | 1313122574202561 |
9 | 213007176660811 |
10 | 49145531401585 |
11 | 14728559289203 |
12 | 5618897042701 |
13 | 2156532ca6018 |
14 | c1c92929c2d3 |
15 | 5a35c4a3dc0a |
hex | 2cb295f10571 |
49145531401585 has 4 divisors (see below), whose sum is σ = 58974637681908. Its totient is φ = 39316425121264.
The previous prime is 49145531401553. The next prime is 49145531401657. The reversal of 49145531401585 is 58510413554194.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 14020860869136 + 35124670532449 = 3744444^2 + 5926607^2 .
It is a cyclic number.
It is not a de Polignac number, because 49145531401585 - 25 = 49145531401553 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4914553140154 + ... + 4914553140163.
It is an arithmetic number, because the mean of its divisors is an integer number (14743659420477).
Almost surely, 249145531401585 is an apocalyptic number.
It is an amenable number.
49145531401585 is a deficient number, since it is larger than the sum of its proper divisors (9829106280323).
49145531401585 is an equidigital number, since it uses as much as digits as its factorization.
49145531401585 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9829106280322.
The product of its (nonzero) digits is 8640000, while the sum is 55.
The spelling of 49145531401585 in words is "forty-nine trillion, one hundred forty-five billion, five hundred thirty-one million, four hundred one thousand, five hundred eighty-five".
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