Base | Representation |
---|---|
bin | 10110010110010100110111… |
… | …01110010011010100000001 |
3 | 20110000021110100021102101001 |
4 | 23023022123232103110001 |
5 | 22420200221333011131 |
6 | 252305105013012001 |
7 | 13231440325620265 |
oct | 1313123356232401 |
9 | 213007410242331 |
10 | 49145628407041 |
11 | 147285a9014901 |
12 | 5618903624001 |
13 | 215654a10b7ba |
14 | c1c9381100a5 |
15 | 5a35cd301261 |
hex | 2cb29bb93501 |
49145628407041 has 2 divisors, whose sum is σ = 49145628407042. Its totient is φ = 49145628407040.
The previous prime is 49145628407039. The next prime is 49145628407053. The reversal of 49145628407041 is 14070482654194.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 35184353089600 + 13961275317441 = 5931640^2 + 3736479^2 .
It is a cyclic number.
It is not a de Polignac number, because 49145628407041 - 21 = 49145628407039 is a prime.
Together with 49145628407039, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (49145628401041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24572814203520 + 24572814203521.
It is an arithmetic number, because the mean of its divisors is an integer number (24572814203521).
Almost surely, 249145628407041 is an apocalyptic number.
It is an amenable number.
49145628407041 is a deficient number, since it is larger than the sum of its proper divisors (1).
49145628407041 is an equidigital number, since it uses as much as digits as its factorization.
49145628407041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7741440, while the sum is 55.
The spelling of 49145628407041 in words is "forty-nine trillion, one hundred forty-five billion, six hundred twenty-eight million, four hundred seven thousand, forty-one".
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