Base | Representation |
---|---|
bin | 10110010110011100011110… |
… | …01001011100001011110011 |
3 | 20110000122222221222222120220 |
4 | 23023032033021130023303 |
5 | 22420232102332303010 |
6 | 252311022142504123 |
7 | 13231643456064663 |
oct | 1313161711341363 |
9 | 213018887888526 |
10 | 49149712384755 |
11 | 1472a3043467a4 |
12 | 5619663295043 |
13 | 2156a4b253c68 |
14 | c1cc046841a3 |
15 | 5a376bb13970 |
hex | 2cb38f25c2f3 |
49149712384755 has 32 divisors (see below), whose sum is σ = 79161733867008. Its totient is φ = 26039121408000.
The previous prime is 49149712384753. The next prime is 49149712384781. The reversal of 49149712384755 is 55748321794194.
It is not a de Polignac number, because 49149712384755 - 21 = 49149712384753 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 49149712384755.
It is not an unprimeable number, because it can be changed into a prime (49149712384753) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 155531460 + ... + 155847150.
It is an arithmetic number, because the mean of its divisors is an integer number (2473804183344).
Almost surely, 249149712384755 is an apocalyptic number.
49149712384755 is a deficient number, since it is larger than the sum of its proper divisors (30012021482253).
49149712384755 is a wasteful number, since it uses less digits than its factorization.
49149712384755 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 384587.
The product of its digits is 304819200, while the sum is 69.
The spelling of 49149712384755 in words is "forty-nine trillion, one hundred forty-nine billion, seven hundred twelve million, three hundred eighty-four thousand, seven hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •