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49156403 is a prime number
BaseRepresentation
bin1011101110000…
…1000100110011
310102111101220112
42323201010303
5100041001103
64513331535
71134552062
oct273410463
9112441815
1049156403
1125824a2a
1214566bab
13a25143a
1467581d9
1544aecd8
hex2ee1133

49156403 has 2 divisors, whose sum is σ = 49156404. Its totient is φ = 49156402.

The previous prime is 49156369. The next prime is 49156409. The reversal of 49156403 is 30465194.

49156403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 49156403 - 26 = 49156339 is a prime.

It is a Sophie Germain prime.

It is equal to p2953355 and since 49156403 and 2953355 have the same sum of digits, it is a Honaker prime.

It is a self number, because there is not a number n which added to its sum of digits gives 49156403.

It is not a weakly prime, because it can be changed into another prime (49156409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24578201 + 24578202.

It is an arithmetic number, because the mean of its divisors is an integer number (24578202).

Almost surely, 249156403 is an apocalyptic number.

49156403 is a deficient number, since it is larger than the sum of its proper divisors (1).

49156403 is an equidigital number, since it uses as much as digits as its factorization.

49156403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 32.

The square root of 49156403 is about 7011.1627423702. The cubic root of 49156403 is about 366.3194951742.

The spelling of 49156403 in words is "forty-nine million, one hundred fifty-six thousand, four hundred three".