Base | Representation |
---|---|
bin | 101101110010001101… |
… | …110100011101010001 |
3 | 11200220002211201122122 |
4 | 231302031310131101 |
5 | 1301140140144432 |
6 | 34330103544025 |
7 | 3360152314553 |
oct | 556215643521 |
9 | 150802751578 |
10 | 49160865617 |
11 | 19938032a66 |
12 | 963ba5b015 |
13 | 4835c672c6 |
14 | 25450d94d3 |
15 | 142ad8c612 |
hex | b72374751 |
49160865617 has 2 divisors, whose sum is σ = 49160865618. Its totient is φ = 49160865616.
The previous prime is 49160865599. The next prime is 49160865619. The reversal of 49160865617 is 71656806194.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46286940736 + 2873924881 = 215144^2 + 53609^2 .
It is a cyclic number.
It is not a de Polignac number, because 49160865617 - 214 = 49160849233 is a prime.
Together with 49160865619, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (49160865619) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24580432808 + 24580432809.
It is an arithmetic number, because the mean of its divisors is an integer number (24580432809).
Almost surely, 249160865617 is an apocalyptic number.
It is an amenable number.
49160865617 is a deficient number, since it is larger than the sum of its proper divisors (1).
49160865617 is an equidigital number, since it uses as much as digits as its factorization.
49160865617 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2177280, while the sum is 53.
The spelling of 49160865617 in words is "forty-nine billion, one hundred sixty million, eight hundred sixty-five thousand, six hundred seventeen".
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