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4917040253 is a prime number
BaseRepresentation
bin1001001010001010…
…00001010001111101
3110200200021112011222
410211011001101331
540032230242003
62131525123125
7232564103216
oct44505012175
913620245158
104917040253
1120a35a5134
12b528594a5
13604903298
1434906840d
151dba1ac38
hex12514147d

4917040253 has 2 divisors, whose sum is σ = 4917040254. Its totient is φ = 4917040252.

The previous prime is 4917040187. The next prime is 4917040279. The reversal of 4917040253 is 3520407194.

4917040253 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4683622969 + 233417284 = 68437^2 + 15278^2 .

It is a cyclic number.

It is not a de Polignac number, because 4917040253 - 28 = 4917039997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4917040283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2458520126 + 2458520127.

It is an arithmetic number, because the mean of its divisors is an integer number (2458520127).

Almost surely, 24917040253 is an apocalyptic number.

It is an amenable number.

4917040253 is a deficient number, since it is larger than the sum of its proper divisors (1).

4917040253 is an equidigital number, since it uses as much as digits as its factorization.

4917040253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30240, while the sum is 35.

The square root of 4917040253 is about 70121.6104564064. The cubic root of 4917040253 is about 1700.4658761236.

The spelling of 4917040253 in words is "four billion, nine hundred seventeen million, forty thousand, two hundred fifty-three".