Base | Representation |
---|---|
bin | 101101110010110101… |
… | …001101110100110010 |
3 | 11200220211021102100102 |
4 | 231302311031310302 |
5 | 1301200311140023 |
6 | 34331113152402 |
7 | 3360336150134 |
oct | 556265156462 |
9 | 150824242312 |
10 | 49171193138 |
11 | 19942947201 |
12 | 96433bb702 |
13 | 4838141c72 |
14 | 2546627054 |
15 | 142bc2c628 |
hex | b72d4dd32 |
49171193138 has 4 divisors (see below), whose sum is σ = 73756789710. Its totient is φ = 24585596568.
The previous prime is 49171193131. The next prime is 49171193167. The reversal of 49171193138 is 83139117194.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 42114017089 + 7057176049 = 205217^2 + 84007^2 .
It is a super-2 number, since 2×491711931382 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 49171193092 and 49171193101.
It is not an unprimeable number, because it can be changed into a prime (49171193131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12292798283 + ... + 12292798286.
Almost surely, 249171193138 is an apocalyptic number.
49171193138 is a deficient number, since it is larger than the sum of its proper divisors (24585596572).
49171193138 is a wasteful number, since it uses less digits than its factorization.
49171193138 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24585596571.
The product of its digits is 163296, while the sum is 47.
The spelling of 49171193138 in words is "forty-nine billion, one hundred seventy-one million, one hundred ninety-three thousand, one hundred thirty-eight".
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