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4921112111293 = 7703016015899
BaseRepresentation
bin100011110011100100100…
…1000111010100010111101
3122102110020202122011022101
41013213021020322202331
51121111414200030133
614244421103145101
71015352513525410
oct107471110724275
918373222564271
104921112111293
111628039548124
126758b25a5191
1329909c490991
1413027c5bdb77
1588021bcc37d
hex479c923a8bd

4921112111293 has 4 divisors (see below), whose sum is σ = 5624128127200. Its totient is φ = 4218096095388.

The previous prime is 4921112111281. The next prime is 4921112111393. The reversal of 4921112111293 is 3921112111294.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 4921112111293 - 217 = 4921111980221 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4921112111263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 351508007943 + ... + 351508007956.

It is an arithmetic number, because the mean of its divisors is an integer number (1406032031800).

Almost surely, 24921112111293 is an apocalyptic number.

It is an amenable number.

4921112111293 is a deficient number, since it is larger than the sum of its proper divisors (703016015907).

4921112111293 is an equidigital number, since it uses as much as digits as its factorization.

4921112111293 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 703016015906.

The product of its digits is 7776, while the sum is 37.

Subtracting from 4921112111293 its reverse (3921112111294), we obtain a palindrome (999999999999).

The spelling of 4921112111293 in words is "four trillion, nine hundred twenty-one billion, one hundred twelve million, one hundred eleven thousand, two hundred ninety-three".

Divisors: 1 7 703016015899 4921112111293