Base | Representation |
---|---|
bin | 100011110011110110110… |
… | …1101101111111010111001 |
3 | 122102111211112022002002002 |
4 | 1013213231231233322321 |
5 | 1121114143242344443 |
6 | 14245002023350345 |
7 | 1015403644405415 |
oct | 107475555577271 |
9 | 18374745262062 |
10 | 4921725746873 |
11 | 1628323969671 |
12 | 675a43bb23b5 |
13 | 299169651b60 |
14 | 1302d9cb5d45 |
15 | 8805a9e02b8 |
hex | 479edb6feb9 |
4921725746873 has 16 divisors (see below), whose sum is σ = 5635122877440. Its totient is φ = 4263611461824.
The previous prime is 4921725746851. The next prime is 4921725746891. The reversal of 4921725746873 is 3786475271294.
It is not a de Polignac number, because 4921725746873 - 28 = 4921725746617 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (4921725746803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 155273033 + ... + 155304726.
It is an arithmetic number, because the mean of its divisors is an integer number (352195179840).
Almost surely, 24921725746873 is an apocalyptic number.
It is an amenable number.
4921725746873 is a deficient number, since it is larger than the sum of its proper divisors (713397130567).
4921725746873 is a wasteful number, since it uses less digits than its factorization.
4921725746873 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 310577848.
The product of its digits is 142248960, while the sum is 65.
The spelling of 4921725746873 in words is "four trillion, nine hundred twenty-one billion, seven hundred twenty-five million, seven hundred forty-six thousand, eight hundred seventy-three".
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