Base | Representation |
---|---|
bin | 1001001010110110… |
… | …11111000101010101 |
3 | 110201002100201200222 |
4 | 10211123133011111 |
5 | 40040232220433 |
6 | 2132255244125 |
7 | 232665132056 |
oct | 44533370525 |
9 | 13632321628 |
10 | 4922929493 |
11 | 20a6957879 |
12 | b54819645 |
13 | 605bb5a41 |
14 | 349b5c72d |
15 | 1dc2d0b98 |
hex | 1256df155 |
4922929493 has 2 divisors, whose sum is σ = 4922929494. Its totient is φ = 4922929492.
The previous prime is 4922929471. The next prime is 4922929511. The reversal of 4922929493 is 3949292294.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2738114929 + 2184814564 = 52327^2 + 46742^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4922929493 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4922929463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2461464746 + 2461464747.
It is an arithmetic number, because the mean of its divisors is an integer number (2461464747).
Almost surely, 24922929493 is an apocalyptic number.
It is an amenable number.
4922929493 is a deficient number, since it is larger than the sum of its proper divisors (1).
4922929493 is an equidigital number, since it uses as much as digits as its factorization.
4922929493 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2519424, while the sum is 53.
The square root of 4922929493 is about 70163.5909357553. The cubic root of 4922929493 is about 1701.1444995521.
The spelling of 4922929493 in words is "four billion, nine hundred twenty-two million, nine hundred twenty-nine thousand, four hundred ninety-three".
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