Base | Representation |
---|---|
bin | 101101110110100001… |
… | …100000101101011001 |
3 | 11201002010211110122000 |
4 | 231312201200231121 |
5 | 1301312140331343 |
6 | 34341204551213 |
7 | 3362020520013 |
oct | 556641405531 |
9 | 151063743560 |
10 | 49233136473 |
11 | 19974905144 |
12 | 96600b2509 |
13 | 4847c1c621 |
14 | 255094d1b3 |
15 | 14323b5ed3 |
hex | b76860b59 |
49233136473 has 32 divisors (see below), whose sum is σ = 76202465280. Its totient is φ = 31356570960.
The previous prime is 49233136429. The next prime is 49233136481. The reversal of 49233136473 is 37463133294.
It is a happy number.
49233136473 is a `hidden beast` number, since 49 + 2 + 3 + 3 + 136 + 473 = 666.
49233136473 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 49233136473 - 29 = 49233135961 is a prime.
It is not an unprimeable number, because it can be changed into a prime (49233136373) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 462918 + ... + 559248.
It is an arithmetic number, because the mean of its divisors is an integer number (2381327040).
Almost surely, 249233136473 is an apocalyptic number.
It is an amenable number.
49233136473 is a deficient number, since it is larger than the sum of its proper divisors (26969328807).
49233136473 is a wasteful number, since it uses less digits than its factorization.
49233136473 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97186 (or 97180 counting only the distinct ones).
The product of its digits is 979776, while the sum is 45.
The spelling of 49233136473 in words is "forty-nine billion, two hundred thirty-three million, one hundred thirty-six thousand, four hundred seventy-three".
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