Base | Representation |
---|---|
bin | 100011110101110110001… |
… | …1011110011001111111111 |
3 | 122102220212100121121120222 |
4 | 1013223230123303033333 |
5 | 1121201421300410444 |
6 | 14250550043131555 |
7 | 1015614565416626 |
oct | 107535433631777 |
9 | 18386770547528 |
10 | 4925999231999 |
11 | 162a11716725a |
12 | 676837213bbb |
13 | 29969ab19791 |
14 | 1305c369a6bd |
15 | 8820ac87eee |
hex | 47aec6f33ff |
4925999231999 has 16 divisors (see below), whose sum is σ = 5010873124608. Its totient is φ = 4841471756352.
The previous prime is 4925999231957. The next prime is 4925999232041. The reversal of 4925999231999 is 9991329995294.
It is an interprime number because it is at equal distance from previous prime (4925999231957) and next prime (4925999232041).
It is a cyclic number.
It is not a de Polignac number, because 4925999231999 - 232 = 4921704264703 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4925999231399) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52758134 + ... + 52851420.
It is an arithmetic number, because the mean of its divisors is an integer number (313179570288).
Almost surely, 24925999231999 is an apocalyptic number.
4925999231999 is a deficient number, since it is larger than the sum of its proper divisors (84873892609).
4925999231999 is an equidigital number, since it uses as much as digits as its factorization.
4925999231999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 95134.
The product of its digits is 1147912560, while the sum is 80.
The spelling of 4925999231999 in words is "four trillion, nine hundred twenty-five billion, nine hundred ninety-nine million, two hundred thirty-one thousand, nine hundred ninety-nine".
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